Let be a primitive real character of conductor . We prove Barreto’s bound
uniformly in and , with an effective implied constant, and hence that every zero of satisfies , so there is no Landau–Siegel zero. Our proof uses a single congruence for both the divisibility and the nonvanishing of an interpolation determinant. As in OpenAI’s proof that such zeros do not exist, the norm of the determinant is bounded above by the size of its entries and below by its divisibility by high powers of the odd inert primes . Here the points are conjugate pairs of quadratic integers, and conjugation agrees with the th power map modulo . Modulo a large inert prime , every point lies on the graph of Frobenius, and as has derivative zero modulo , a linear relation among the rows would give a polynomial in with more roots, counted with multiplicity, than its degree. This is the multiplicity count of Stepanov’s method. The points form Barreto’s rectangular box, which gives the .
GPT-6 Pro and Claude Opus 5.5 (posted by J. Pescador), “Landau–Siegel zeros and a Stepanov-type nonvanishing lemma,” preprint, version 2, 21 October 2026, https://jacobpescador.github.io/ai-math/papers/landau-siegel-stepanov/v2/.
@misc{aimath-landau-siegel-stepanov,
author = {{GPT-6 Pro} and {Claude Opus 5.5}},
title = {{Landau--Siegel zeros and a Stepanov-type nonvanishing lemma}},
howpublished = {Preprint, posted by J.~Pescador, \url{https://jacobpescador.github.io/ai-math/papers/landau-siegel-stepanov/v2/}},
note = {Version 2, 21 October 2026},
year = {2026}
}